Eureka Math Grade 4 Module 5 Lesson 16 Answer Key (2024)

Engage NY Eureka Math 4th Grade Module 5 Lesson 16 Answer Key

Eureka Math Grade 4 Module 5 Lesson 16 Problem Set Answer Key

Question 1.
Solve.
a. 3 fifths – 1 fifth = _____2 __fifths_____

Answer:
3 fifths – 1 fifth = 2 fifths.

Explanation:
In the above-given question,
given that,
3 fifths = 3/5.
3/5 = 0.6.
1 fifth = 1/5.
1/5 = 0.2.
0.6 – 0.2 = 0.4.
2/5 = 0.4.
3 fifths – 1 fifth = 2 fifths.

b. 5 fifths – 3 fifths = _____2_fifths._________

Answer:
5 fifths – 3 fifth = 2 fifths.

Explanation:
In the above-given question,
given that,
5 fifths = 5/5.
5/5 = 1.
3 fifth = 3/5.
3/5 = 0.6.
1 – 0.6 = 0.4.
2/5 = 0.4.
3 fifths – 1 fifth = 2 fifths.

c. 3 halves – 2 halves = _____1_ halves._____

Answer:
3 halves – 2 halves = 1 halves

Explanation:
In the above-given question,
given that,
3 halves = 3/2.
3/2 = 1.5.
2 halves = 2/2.
2/2 = 1.
1.5 – 1 = 0.5.
1/2 = 0.5.
3 halves – 2 halves = 1 half.

d. 6 fourths – 3 fourths = ____3__fourths._______

Answer:
6 fourths – 3 fourths = 3 fourths.

Explanation:
In the above-given question,
given that,
6 fourths = 6/4.
6/4 = 1.5.
3 fourths = 3/4.
3/4 = 0.75.
1.5 – 0.75 = 0.75.
3/4 = 0.75.
6 fourths – 3 fourths = 3 fourths.

Question 2.
Solve.

a. \(\frac{5}{6}\) – \(\frac{3}{6}\)

Answer:
\(\frac{5}{6}\) – \(\frac{3}{6}\) = \(\frac{2}{6}\)

Explanation:
In the above-given question,
given that,
5 sixths = 5/6.
5/6 = 0.83.
3 sixths = 3/6.
3/6 = 0.5.
0.83 – 0.5 = 0.33.
2/6 = 0.33.
\(\frac{5}{6}\) – \(\frac{3}{6}\) = \(\frac{2}{6}\)

b. \(\frac{6}{8}\) – \(\frac{4}{8}\)

Answer:
\(\frac{6}{8}\) – \(\frac{4}{8}\) = \(\frac{2}{8}\)

Explanation:
In the above-given question,
given that,
6 eights = 6/8.
6/8 = 0.75.
4 eights = 4/8.
4/8 = 0.5.
0.75 – 0.5 = 0.25.
2/8 = 0.25.
\(\frac{6}{8}\) – \(\frac{4}{8}\) = \(\frac{2}{8}\)

c. \(\frac{3}{10}\) – \(\frac{3}{10}\)

Answer:
\(\frac{3}{10}\) – \(\frac{3}{10}\) = \(\frac{0}{0}\)

Explanation:
In the above-given question,
given that,
3 tens = 3/10.
3/10 = 0.3.
3 tens = 3/10.
3/10 = 0.3.
0.3 – 0.3 = 0.
0/6 = 0.
\(\frac{3}{10}\) – \(\frac{3}{10}\) = \(\frac{0}{0}\)

d. \(\frac{5}{5}\) – \(\frac{4}{5}\)

Answer:
\(\frac{5}{5}\) – \(\frac{4}{5}\) = \(\frac{1}{5}\)

Explanation:
In the above-given question,
given that,
5 fifths = 5/5.
5/5 = 1.
4 fifths = 4/5.
4/5 = 0.8.
1 – 0.8 = 0.2.
1/5 = 0.2.
\(\frac{5}{5}\) – \(\frac{4}{5}\) = \(\frac{1}{5}\)

e. \(\frac{5}{4}\) – \(\frac{4}{4}\)

Answer:
\(\frac{5}{4}\) – \(\frac{4}{4}\) = \(\frac{1}{4}\)

Explanation:
In the above-given question,
given that,
5 fours = 5/4.
5/4 = 1.25.
4 fours = 4/4.
4/4 = 1.
1.25 – 1 = 0.25.
1/4 = 0.25.
\(\frac{5}{4}\) – \(\frac{4}{4}\) = \(\frac{1}{4}\)

f. \(\frac{5}{4}\) – \(\frac{3}{4}\)

Answer:
\(\frac{5}{4}\) – \(\frac{3}{4}\) = \(\frac{2}{4}\)

Explanation:
In the above-given question,
given that,
5 fours = 5/4.
5/4 = 1.25.
3 fours = 3/4.
3/4 = 0.75.
1.25 – 0.75 = 0.5.
2/4 = 0.5.
\(\frac{5}{4}\) – \(\frac{3}{4}\) = \(\frac{2}{4}\)

Question 3.
Solve. Use a number bond to show how to convert the difference to a mixed number. Problem (a) has been completed for you.
a. Eureka Math Grade 4 Module 5 Lesson 16 Answer Key (1)

Answer:
12/8 – 3/8 = 9/8.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
12/8 – 3/8.
9/8.
9/8 = 8/8 + 1/8.

b. \(\frac{12}{6}\) – \(\frac{5}{6}\)

Answer:
12/6 – 5/6 = 7/6.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
12/6 – 5/6.
7/6.
7/6 = 6/6 + 1/6.

c. \(\frac{9}{5}\) – \(\frac{3}{5}\)

Answer:
9/5 – 3/5 = 6/5.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
9/5 – 3/5.
6/5.
6/5 = 5/5 + 1/5.

d. \(\frac{14}{8}\) – \(\frac{3}{8}\)

Answer:
14/8 – 3/8 = 11/8.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
14/8 – 3/8.
11/8.
11/8 = 8/8 + 3/8.

e. \(\frac{8}{4}\) – \(\frac{2}{4}\)

Answer:
8/4 – 2/4 = 6/4.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
8/4 – 2/4.
6/4.
6/4 = 4/4 + 2/4.

f. \(\frac{15}{10}\) – \(\frac{3}{10}\)

Answer:
15/10 – 3/10 = 7/10.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
15/10 – 3/10.
7/10.
7/10 = 10/10 + 1/6.

Question 4.
Solve. Write the sum in unit form.

a. 2 fourths + 1 fourth = _3 fourths._

Answer:
2 fourths + 1 fourth = 3 fourths.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
2 fourths = 1/4 + 1/4.
2 fourths + 1 fourth = 3 fourths.
1/4 + 1/4 + 1/4 = 3/4.

b. 4 fifths + 3 fifths = ____7__fifths.___

Answer:
4 fifths + 3 fifths = 7 fifths.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
4 fifths = 1/5 + 1/5 + 1/5 + 1/5.
3 fifths = 1/5 + 1/5 + 1/5.
4 fifths + 3 fifths = 7 fifths.
1/5 + 1/5 + 1/5 + 1/5 + 1/5 + 1/5 + 1/5 = 7/5.

Question 5.
Solve.
a. \(\frac{2}{8}\) + \(\frac{5}{8}\)

Answer:
\(\frac{2}{8}\) + \(\frac{5}{8}\) = \(\frac{7}{8}\)

Explanation:
In the above-given question,
given that,
2 eights = 2/8.
2/8 = 0.25.
5 eights = 5/8.
5/8 = 0.625.
0.25 + 0.625 = 0.875.
7/8 = 0.875.
\(\frac{2}{8}\) + \(\frac{5}{8}\) = \(\frac{7}{8}\)

b. \(\frac{4}{12}\) + \(\frac{5}{12}\)

Answer:
\(\frac{4}{12}\) + \(\frac{5}{12}\) = \(\frac{9}{12}\)

Explanation:
In the above-given question,
given that,
4 twelfths = 4/12.
4/12 = 0.33.
5 twelfths = 5/12.
5/12 = 0.41.
0.33 + 0.41 = 0.74.
9/12 = 0.74.
\(\frac{4}{12}\) + \(\frac{5}{12}\) = \(\frac{9}{12}\)

Question 6.
Solve. Use a number bond to decompose the sum. Record your final answer as a mixed number.
Problem (a) has been completed for you.

a. Eureka Math Grade 4 Module 5 Lesson 16 Answer Key (2)

Answer:
3/5 + 4/5 = 7/5.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
3/5 + 4/5.
7/5.
7/5 = 5/5 + 2/5.

b. \(\frac{4}{4}\) + \(\frac{3}{4}\)

Answer:
4/4 + 3/4 = 7/4.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
4/4 + 3/4.
7/4.
7/4 = 4/4 + 3/4.

c. \(\frac{6}{9}\) + \(\frac{6}{9}\)

Answer:
6/9 + 6/9 = 12/9.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
6/9 + 6/9.
12/9.
12/9 = 9/9 + 3/9.

d. \(\frac{7}{10}\) + \(\frac{6}{10}\)

Answer:
7/10 + 6/10 = 13/10.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
7/10 + 6/10.
13/10.
13/10 = 10/10 + 3/10.

e. \(\frac{5}{6}\) + \(\frac{7}{6}\)

Answer:
5/6 + 7/6 = 12/6.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
5/6 + 7/6.
12/6.
12/6 = 6/6 + 7/6.

f. \(\frac{9}{8}\) + \(\frac{5}{8}\)

Answer:
9/8 + 5/8 = 14/8.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
9/8 + 5/8.
14/8.
14/8 = 8/8 + 6/8.

Question 7.
Solve. Use a number line to model your answer.
a. \(\frac{7}{4}\) – \(\frac{5}{4}\)

Answer:
\(\frac{7}{4}\) – \(\frac{5}{4}\) = \(\frac{2}{4}\)

Explanation:
In the above-given question,
given that,
7 fours = 7/4.
7/4 = 1.75.
5 fours = 5/4.
5/4 = 1.25.
1.75 – 1.25 = 0.5.
2/4 = 0.5.
\(\frac{7}{4}\) – \(\frac{5}{4}\) = \(\frac{2}{4}\)

b. \(\frac{5}{4}\) + \(\frac{2}{4}\)

Answer:
5/4 + 2/4 = 7/4.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
5/4 + 2/4.
7/4.
7/4 = 4/4 + 3/4.

Eureka Math Grade 4 Module 5 Lesson 16 Exit Ticket Answer Key

Question 1.
Solve. Use a number bond to decompose the difference. Record your final answer as a mixed number.
\(\frac{16}{9}\) – \(\frac{5}{9}\)

Answer:
16/9 – 5/9 = 11/9.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
16/9 – 5/9.
11/9.
11/9 = 9/9 + 2/9.

Question 2.
Solve. Use a number bond to decompose the sum. Record your final answer as a mixed number.
\(\frac{5}{12}\) + \(\frac{10}{12}\)

Answer:
5/12 + 10/12 = 15/12.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
5/12 + 10/12.
15/12.
15/12 = 12/12 + 3/12.

Eureka Math Grade 4 Module 5 Lesson 16 Homework Answer Key

Question 1.
Solve.
a. 3 sixths – 2 sixths = __1__sixths___________

Answer:
3 sixths – 2 sixths = 1 sixths.

Explanation:
In the above-given question,
given that,
3 sixths = 3/6.
3/6 = 0.5.
2 sixths = 2/6.
2/6 = 0.33.
0.5 – 0.3 = 0.1.
1/6 = 0.1.

b. 5 tenths – 3 tenths = ___2 tenths._____

Answer:
5 tenths – 3 tenths = 2 tenths.

Explanation:
In the above-given question,
given that,
5 tenths = 5/10.
5/10 = 0.5.
3 tenths = 3/10.
3/10 = 0.3.
0.5 – 0.3 = 0.2.
2/10 = 0.2.

c. 3 fourths – 2 fourths = ____1__fourth._________

Answer:
3 fourths – 2 fourths = 1 fourth.

Explanation:
In the above-given question,
given that,
3 fourths = 3/4.
3/4 = 0.75.
2 fourths = 2/4.
2/4 = 0.5.
0.75 – 0.5 = 0.25.
1/4 = 0.25.

d. 5 thirds – 2 thirds = ___3__thirds._____

Answer:
5 thirds – 2 thirds = 3 thirds.

Explanation:
In the above-given question,
given that,
5 thirds = 5/3.
3/5 = 1.6.
2 thirds = 2/3.
2/3 = 0.6.
1.6 – 0.6 = 1.
3/3 = 1.

Question 2.
Solve.

a. \(\frac{3}{5}\) – \(\frac{2}{5}\)

Answer:
\(\frac{3}{5}\) – \(\frac{2}{5}\) = \(\frac{1}{5}\)

Explanation:
In the above-given question,
given that,
3 fives = 3/5.
3/5 = 0.6.
2 fives = 2/5.
2/5 = 0.4.
0.6 – 0.4 = 0.2.
1/5 = 0.2.
\(\frac{3}{5}\) – \(\frac{2}{5}\) = \(\frac{1}{5}\)

b. \(\frac{7}{9}\) – \(\frac{3}{9}\)

Answer:
\(\frac{7}{9}\) – \(\frac{3}{9}\) = \(\frac{4}{9}\)

Explanation:
In the above-given question,
given that,
7 nines = 7/9.
7/9 = 0.7.
3 nines = 3/9.
3/9 = 0.3.
0.7 – 0.3 = 0.4.
4/9 = 0.4.
\(\frac{7}{9}\) – \(\frac{3}{9}\) = \(\frac{4}{9}\)

c. \(\frac{7}{12}\) – \(\frac{3}{12}\)

Answer:
\(\frac{7}{12}\) – \(\frac{3}{12}\) = \(\frac{4}{12}\)

Explanation:
In the above-given question,
given that,
7 twelfths = 7/12.
7/12 = 0.58.
3 twelfths = 3/12.
3/12 = 0.25.
0.58 – 0.25 = 0.33.
4/12 = 0.33.
\(\frac{7}{12}\) – \(\frac{3}{12}\) = \(\frac{4}{12}\)

d. \(\frac{6}{6}\) – \(\frac{4}{6}\)

Answer:
\(\frac{6}{6}\) – \(\frac{4}{6}\) = \(\frac{2}{6}\)

Explanation:
In the above-given question,
given that,
6 sixs = 6/6.
6/6 = 1.
4 sixs = 4/6.
4/6 = 0.6.
1 – 0.6 = 0.4.
2/6 = 0.4.
\(\frac{6}{6}\) – \(\frac{4}{6}\) = \(\frac{2}{6}\)

e. \(\frac{5}{3}\) – \(\frac{2}{3}\)

Answer:
\(\frac{5}{3}\) – \(\frac{2}{3}\) = \(\frac{3}{3}\)

Explanation:
In the above-given question,
given that,
5 threes = 5/3.
5/3 = 1.6.
2 threes = 2/3.
2/3 = 0.6.
1.25 – 1 = 0.25.
3/3 = 1.
\(\frac{5}{3}\) – \(\frac{2}{3}\) = \(\frac{3}{3}\)

f. \(\frac{7}{4}\) – \(\frac{5}{4}\)

Answer:
\(\frac{7}{4}\) – \(\frac{5}{4}\) = \(\frac{3}{4}\)

Explanation:
In the above-given question,
given that,
7 fours = 7/4.
7/4 = 1.75.
5 fours = 4/4.
5/4 = 1.25.
1.75 – 1.25 = 0.75.
3/4 = 0.75.
\(\frac{7}{4}\) – \(\frac{5}{4}\) = \(\frac{3}{4}\)

Question 3.
Solve. Use a number bond to decompose the difference. Record your final answer as a mixed number. Problem (a) has been completed for you.
Eureka Math Grade 4 Module 5 Lesson 16 Answer Key (3)

Answer:
12/6 – 3/6 = 9/6.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
12/6 – 3/4.
9/6.
9/6 = 6/6 + 3/6.

b. \(\frac{17}{8}\) – \(\frac{6}{8}\)

Answer:
17/8 – 6/8 = 11/8.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
17/8 – 6/8.
11/8.
11/8 = 8/8 + 2/8.

c. \(\frac{9}{5}\) – \(\frac{3}{5}\)

Answer:
9/5 – 3/5 = 6/5.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
9/5 – 3/5.
6/5.
6/5 = 5/5 + 1/6.

d. \(\frac{11}{4}\) – \(\frac{6}{4}\)

Answer:
11/4 – 6/4 = 5/4.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
11/4 – 6/4.
5/4.
5/4 = 4/4 + 1/4.

e. \(\frac{10}{7}\) – \(\frac{2}{7}\)

Answer:
10/7 – 2/7 = 8/7.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
10/7 – 2/7.
8/7.
8/7 = 7/7 + 1/7.

f. \(\frac{21}{10}\) – \(\frac{9}{10}\)

Answer:
21/10 – 9/10 = 11/10.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
21/10 – 9/10.
11/10.
11/10 = 10/10 + 1/10.

Question 4.
Solve. Write the sum in unit form.
a. 4 fifths + 2 fifths = ____6__fifths.____

Answer:
4 fifths + 2 fifths = 6 fifths.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
4 fifths = 1/5 + 1/5 + 1/5 + 1/5.
2 fifths = 1/5 + 1/5.
4 fifths + 2 fifth = 6 fifths.
1/5 + 1/5 + 1/5 + 1/5 + 1/5 + 1/5 = 6/5.

b. 5 eighths + 2 eighths = __7___eights.______

Answer:
5 eights + 2 eighths = 7 eights.

Explanation:
In the above-given question,
given that,
Use a number bond to show how to convert the difference to a mixed number.
5 eights = 1/8 + 1/8 + 1/8 + 1/8 + 1/8.
2 eights = 1/8 + 1/8.
5 eights + 2 eights = 7 eights.
1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 = 7/8.

Question 5.
Solve.
a. \(\frac{3}{11}\) + \(\frac{6}{11}\)

Answer:
3/11 + 6/11 = 9/11.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
3/11 + 6/11.
9/11.
9/11 = 3/11 + 9/11.

b. \(\frac{3}{10}\) + \(\frac{6}{10}\)

Answer:
3/10 + 6/10 = 9/10.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
3/10 + 6/10.
9/10.
9/10 = 3/10 + 6/10.

Question 6.
Solve. Use a number bond to decompose the sum. Record your final answer as a mixed number.
a. \(\frac{3}{4}\) + \(\frac{3}{4}\)

Answer:
3/4 + 3/4 = 6/4.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
3/4 + 3/4.
6/4.
6/4 = 4/4 + 5/4.

b. \(\frac{8}{12}\) + \(\frac{6}{12}\)

Answer:
8/12 + 6/12 = 14/12.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
8/12 + 6/12.
14/12.
14/12 = 12/12 + 2/12.

c. \(\frac{5}{8}\) + \(\frac{7}{8}\)

Answer:
5/8 + 7/8 = 12/8.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
5/8 + 7/8.
12/8.
12/8 = 8/8 + 4/8.

d. \(\frac{8}{10}\) + \(\frac{5}{10}\)

Answer:
8/10 + 5/10 = 13/10.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
8/10 + 5/10.
13/10.
13/10 = 10/10 + 3/10.

e. \(\frac{3}{5}\) + \(\frac{6}{5}\)

Answer:
3/5 + 6/5 = 9/5.

Explanation:
In the above-given question,
given that,
Use a number bond to decompose the sum.
3/5 + 6/5.
9/5.
9/5 = 5/5 + 4/5.

Question 7.
Solve. Use a number line to model your answer.

a. \(\frac{11}{9}\) – \(\frac{5}{9}\)

Answer:
\(\frac{11}{9}\) – \(\frac{5}{9}\) = \(\frac{6}{9}\)

Explanation:
In the above-given question,
given that,
11 nines = 11/9.
11/9 = 0.58.
5 nines = 5/9.
5/9 = 0.25.
0.58 – 0.25 = 0.33.
6/9 = 0.33.
\(\frac{11}{9}\) – \(\frac{5}{9}\) = \(\frac{6}{1}\)

b. \(\frac{13}{12}\) + \(\frac{4}{12}\)

Eureka Math Grade 4 Module 5 Lesson 16 Answer Key (2024)

FAQs

Is Eureka Math a curriculum? ›

Eureka Math® is a holistic Prekindergarten through Grade 12 curriculum that carefully sequences mathematical progressions in expertly crafted modules, making math a joy to teach and learn. We provide in-depth professional development, learning materials, and a community of support.

What are the four core components of a Eureka Math TEKS lesson? ›

Lesson Components

Within every lesson, students experience the same four core components: - Fluency Practice, - Application Problem, - Concept Development (which includes a Problem Set), and - Student Debrief (which includes an Exit Ticket).

Is Eureka Math good or bad? ›

Is Eureka Math a good curriculum? The answer to this question depends on the target audience. If you're a teacher in a public school who needs to cover State Standards and your goal is merely to prepare students for State tests, then Eureka may be a good curriculum for you.

Is Eureka Math no longer free? ›

Is Eureka Math free? Yes. Anyone can download the entire PK–12 Eureka Math curriculum, along with a variety of instructional materials and support resources, for free.

Is Eureka Math developmentally appropriate? ›

Eureka Math is a math curriculum developed by a team of math master teachers and mathematicians to ensure that the quality of the curriculum builds upon students' prior-knowledge and teaches mathematical concepts and skills in a coherent and developmentally-appropriate way.

What is the most used math curriculum? ›

According to the RAND Corporation, over 50% of U.S. school teachers DFFHVV Eureka Math or the version of the curriculum found on the EngageNY website. Additionally, Eureka Math is the only curriculum found by EdReports.org to align fully with the Common Core State Standards for Mathematics for all grades, K–8.

Does Eureka Math have workbooks? ›

In addition to our Learn, Practice, Succeed configuration you can get student workbooks, teacher editions, and assessment and fluency materials for Grades PK–12. These materials are also available in Spanish for Grades K–8.

Does Khan Academy align with Eureka Math? ›

To access our aligned resources, go to the Courses dropdown menu in the top left corner of your screen and select See all Math. From the Math page you can view all Math courses including the courses aligned to the Eureka Math/EngageNY curriculum.

References

Top Articles
Latest Posts
Article information

Author: Neely Ledner

Last Updated:

Views: 6106

Rating: 4.1 / 5 (62 voted)

Reviews: 93% of readers found this page helpful

Author information

Name: Neely Ledner

Birthday: 1998-06-09

Address: 443 Barrows Terrace, New Jodyberg, CO 57462-5329

Phone: +2433516856029

Job: Central Legal Facilitator

Hobby: Backpacking, Jogging, Magic, Driving, Macrame, Embroidery, Foraging

Introduction: My name is Neely Ledner, I am a bright, determined, beautiful, adventurous, adventurous, spotless, calm person who loves writing and wants to share my knowledge and understanding with you.